How to think ? Differentiability short tricks #maths #knowledge #csirnet
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YouTubeDr.Gajendra Purohit - GATE / IIT JAM / CSIR NET
How to think ? Differentiability short tricks #maths #knowledge #csirnet
Differentiability of (|x|), (|x|^2), and (|x|^3) | Calculus Shorts In this short, we compare the differentiability of three important absolute value functions: * (|x|) – Not differentiable at (x = 0) * (|x|^2 = x^2) – Differentiable everywhere * (|x|^3) – Differentiable everywhere, including at (x = 0) Learn why these functions behave ...
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Q) The following graph represents (A) 𝑦=cos^(βˆ’1) π‘₯ (B) 𝑦=sec^(βˆ’1) π‘₯ (C) 𝑦=sin^(βˆ’1) π‘₯ (D)
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Q) If 𝑦=sin^(βˆ’1) π‘₯,then (1βˆ’π‘₯^2 ) (𝑑^2 𝑦)/(𝑑π‘₯^2 ) is equal to #differentiation #cbse2027 #cbs
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Q) If 𝑦=sin^(βˆ’1) π‘₯,then (1βˆ’π‘₯^2 ) (𝑑^2 𝑦)/(𝑑π‘₯^2 ) is equal to #differentiation #cbse2027 #cbs
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How to think ?Matix short tricks #maths #knowledge #csirnet #iitjam
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Q) Show that the derivative of tan^(βˆ’1) (secπ‘₯+tanπ‘₯),[βˆ’πœ‹/2π‘₯πœ‹/2] with respect to x is equal to 1
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Q) If π‘₯=3sin tβˆ’sin 3t,y=3cos tβˆ’cos 3t find dy/dπ‘₯ and prove that (d^2 y)/(dπ‘₯^2 )=(βˆ’cosec^3 2tβ‹…cos
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Q) Show that the derivative of tan^(βˆ’1) (secπ‘₯+tanπ‘₯),[βˆ’πœ‹/2π‘₯πœ‹/2] with respect to x is equal to 1
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Q) Show that the derivative of tan^(βˆ’1) (secπ‘₯+tanπ‘₯),[βˆ’πœ‹/2π‘₯πœ‹/2] with respect to x is equal to 1
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Q) The following graph represents (A) 𝑦=cos^(βˆ’1) π‘₯ (B) 𝑦=sec^(βˆ’1) π‘₯ (C) 𝑦=sin^(βˆ’1) π‘₯ (D)
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Q) The following graph represents (A) 𝑦=cos^(βˆ’1) π‘₯ (B) 𝑦=sec^(βˆ’1) π‘₯ (C) 𝑦=sin^(βˆ’1) π‘₯ (D)
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Q) If 𝑦=sin^(βˆ’1) π‘₯,then (1βˆ’π‘₯^2 ) (𝑑^2 𝑦)/(𝑑π‘₯^2 ) is equal to #differentiation #cbse2027 #cbs
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Q) Find the value of k, so that f(x)={ ((kcos x)/(πœ‹βˆ’2x),if xβ‰ πœ‹/2 3, if x=πœ‹/2) is contin
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YouTubeShivang Maths Academy
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Q) If 𝑦=π‘Žcos(logπ‘₯)+𝑏sin(logπ‘₯), then π‘₯^2 𝑦_2+π‘₯𝑦_1 is #continuityanddifferentiationclass12
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